A bag contains coins of four denomiations Viz. 1 rupees, 50 paisa, 25 paisa and 10 paisa
There are as many 50 paisa coins as the value of 25 paisa coins in a rupee. The value of
a 1 rupee coins is 5 times the value of 50 paisa coins. The ratio of the number of 10 paisa coins
to that of 1 rupee coin is 4:3, while the total number of coins in the bag is 325. How many 10 paise coins are there?

• If
  a = number of 1 rupee coins
  b = number of 50 paise coins
  c = number of 25 paise coins
  d = number of 10 paise coins
  
  
  then four equations are
  a+b+c+d = 325
  d/a = 4/3 or d= a*4/3
  100a= 5*50*b or b= a*2/5 as The value of a 1 rupee coins is 5 times the value of 50 paisa coins.
  b=c/4 as There are as many 50 paisa coins as the value of 25 paisa coins in a rupee
  
  solving these eqns, we get
  a=75 coins
  d=a*4/3= 75*4/3=100..... answer
  b= 75*2/5= 30
  c=4b = 120
  
• 11 years agoHelpfull: Yes(5) No(3)
• The equations i got:
  a = number of 1 rupee coins
  b = number of 50 paise coins
  c = number of 25 paise coins
  d = number of 10 paise coins
  
  so :
  total number of coins in the bag is 325
  1) a+b+c+d = 325
  ratio of the number of 10 paisa coins to that of 1 rupee coin is 4:3
  d/a = 4/3
  2) 3d = 4a
  The value of a 1 rupee coins is 5 times the value of 50 paisa coins
  a = 5 * 2d
  3)a= 10d
  There are as many 50 paisa coins as the value of 25 paisa coins in a rupee
  4) b =4c
  
  I got these 4 equations however I am not getting a value
• 11 years agoHelpfull: Yes(2) No(3)