i need help with this one problem. Find three consecutive even integers such that three times the middle integer is six more than the summ of the first and third.

• let the three numbers be x, x+1, x+2
  3(x+1)-6= x+(x+2)
  3x-3=2x+2
  x=5
  so the numbers are 5,6 and 7
• 7 years agoHelpfull: Yes(0) No(0)