exam Maths Puzzle Numerical Ability

I need to solve the equation cos^2(theta) = 4sin(theta)+4, on the interval 0<(theta)<2pi. I thought I had simplified it correctly using trig identities, but something went wrong. Thanks!

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PLease help to simplify

4i^7 - the square root of -5 times the square root of -5 + the square root of 7 times the square root of -7 - the square root of -16
sqrt4(sqrt32+3sqrt8)