two circles of radius 4 cm and 9 cm respectively touch each other externally at a point and a common tangent touches them at the points P and Q respectively. Then the area fo a square with one side PQ, is

• Length of common Tangent of two externally touching circles = √(4×r1×r2)
  --------> where r1 and r2 are radius of circles
  
  => Length of Tangent = √(4×9×4) = 12 cm
  => Area = 144 sq.cm
• 12 years agoHelpfull: Yes(4) No(8)
• √(r1+r2)^2-(r2-r1)^2
  Area= ans^2
• 8 years agoHelpfull: Yes(1) No(2)