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for which of the following n is the numeber 2^74 + 2^2058 + 2^2n a perfect square
A.2010
B.2011
C.2012
D.2100
Read Solution (Total 4)
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- n = 2020
(a + b) = (a^2 + b^2 + 2ab )
a = 2^37 , b = 2^2020
=> 2^74 + 2^(2*2020) + 2^2058 is a perfect square - 11 years agoHelpfull: Yes(11) No(2)
- 2^37+2*2^2020*2^37+2^2n
so n=2020 - 11 years agoHelpfull: Yes(5) No(1)
- 2^(37*2)+2^(1029*2)+2^(n*2)
we see that ,2's power no. is multiple of (odd no.*2)
thats why.....'n' must be odd no. and only 2011 is odd no.
ans is 2011 - 11 years agoHelpfull: Yes(4) No(5)
- 30/100*20/100*100/50 Ans: A=3 B=25
- 11 years agoHelpfull: Yes(0) No(6)
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