Q. The sum of 8 consecutive odd number is 656.Also average of four consecutive even no is 87.what is the sum of the smallest odd number and second largest even number?

Option
1) 165
2) 175
3) 163
4) Cannot be determined
5) None of these

• sum of 8 no.is=656
  so avg= 656/8=82
  s0. no. are 75,77,79,81,83,85,87,89
  avg of even no. is=87
  so no. are 84,86,88,90
  o sum=75+88=163
• 11 years agoHelpfull: Yes(12) No(3)
• According to question , the numbers are consecutive.so,they must be in AP.
  
  so, let first number be A.
  
  (8/2)*(2A+7*2)=656
  =>A=75
  
  Similarly, let first even number be B.
  (4/2)*(2B+6)=87*4
  => B=84
  so, even numbers are 84,86,88,92
  so, SUM=88+75=163
  
  3 is the right answer.
• 11 years agoHelpfull: Yes(6) No(2)
• suppose
  eight consecutive odd no.is x+x+2+x+4+x+6+x+8+x+10+x+12=656
  so 8x+56=656
  x=75 i.e first no 75 so next no. is 75+2=77
  79,81,83,85,87,89
  now given avg. of even no. is 87
  so remaining four even no. is 84,86,88,90
  so sum=75+88=163
  
  
• 10 years agoHelpfull: Yes(1) No(1)
• 3)163
  75+77+79+81+83+85+87+89=256,
  84+86+88+90/4=87,
  then 75+88=163
  
• 11 years agoHelpfull: Yes(0) No(1)
• sum of 8 consecutive odd numbers are 75,77,79,81,83,85,87,89
  avd of 4 consecutive even numbers are 84,86,88,90
  the ans is 75+88=163
• 11 years agoHelpfull: Yes(0) No(1)