25 persons are in a room. 15 of them play hockey, 17 of them play football and 10 of them play both hockey and football.then no. of person playing neither hockey nor football is
(1).2
(2).17
(3).13
(4).3

• 10 plays both hockey n football
  subtarct 10 from 15 n 17
  we are left with 5+7=12
  total persons are 25
  10 person plays both n 12 persons plays one from two
  so 25-(10+12)=3(plays neither of the two games)
• 11 years agoHelpfull: Yes(5) No(1)
• p(not(h or b)=p(h or b)-[p(h)+p(b)-p(h and b)]
  25-[(15+17-10)]
  =3
  
  
  
• 11 years agoHelpfull: Yes(4) No(0)
• no. of person playing neither hockey nor football is 3.
• 11 years agoHelpfull: Yes(2) No(0)
• total persons=25
  hockey plays=15 person
  football plays=17 person
  both hockey and football plays=10 person
  subtract 10 from hockey players and football players
  we get 7+5=12
  now 25-(10+12)=3
  who plays neither hockey nor football
• 11 years agoHelpfull: Yes(2) No(0)
• 10 play hockey and football so the remaining in the hockey only category is 5 and football only is 7 which gives us a total of 22. remaining persons is 3!
• 8 years agoHelpfull: Yes(2) No(0)
• 25-(15+17-10)=3
• 11 years agoHelpfull: Yes(0) No(0)
• 13.......................................................
• 10 years agoHelpfull: Yes(0) No(3)
• CORRECT ANS IS 3
  
• 9 years agoHelpfull: Yes(0) No(0)
• No of person playing neither hockey nor football is =25-((15+17)-10)
  =3
• 7 years agoHelpfull: Yes(0) No(0)