. The average of four consecutive
numbers A, B, C and D respectively
is 49.5. What is the product of B & D?
(1) 2499 (2) 2352
(3) 2450 (4) 2550
(5) None of these

• 2499
  let four consecutive no.s be X,x+1,x+2,x+3
  then avg. is given as 49.5 therefore...equation will become..
  (x+X+1+x+2+x+3)/4 =49.5
  4x+6=198
  x=48
  hence b,d will be49 and 51..hence..b*d=49*51=2499
• 11 years agoHelpfull: Yes(27) No(5)
• (A+B+C+D)/4 is 49.5. Therefore, A+B+C+D=198
  Let the first consecutive number be x.
  therefore the x+(x+1)+(x+2)+(x+3)=198
  => 4x+6=198
  => x=48
  therefore, the consecutive numbers are
  48,49,50,51.
  Q. product of B&D
  => 49*51=2499.
  answer is option(1).
• 11 years agoHelpfull: Yes(5) No(0)
• 2499
  49*51=2499
  numbers are 48,49,50,51
• 11 years agoHelpfull: Yes(3) No(4)
• sum of a,b,c,d=198(~200).if we divide 200 in 4 equal parts then 50,50,so on...so mid term might be 50.If try to add 48+49+50+51=198.then 49*51=2499
• 11 years agoHelpfull: Yes(2) No(2)
• 1. 2499 consider 4 numbers are x,2x,3x and 4x.
  (x+2x+3x+4x)/4=49.5
  
• 11 years agoHelpfull: Yes(1) No(6)
• let x,(x+1),(x+2)and(x+3)are the four cosecutive numbers.
  i.e A=x, B=(x+1), C=(x+2), D=(x+3).
  x+(x+1)+(x+2)+(x+3)=198
  4x+6=198
  4x=192
  x=192/4=48
  x=48
  i.e A=48,B=49,C=50,D=51
  now B*D=49*51=2499
  Option 1 is Right.
• 11 years agoHelpfull: Yes(1) No(0)
• (1) 2499
  let the four numbers be n-2,n-1,n,n+1
  
• 11 years agoHelpfull: Yes(1) No(0)
• x+x+1+x+2+x+3/4=49.5
  4x+6=198
  4x=192
  x=48
  b=49
  d=51
  b*d=49*51=2499
• 6 years agoHelpfull: Yes(1) No(0)
• (48+49+50+51)/4=198
  
  50*51=2550
  
  So, its simple... last 2 nos are 50 & 51.
• 11 years agoHelpfull: Yes(0) No(5)
• let take three consecutive numbers x+2,x+4,x+6,x+8
  the avg of 4 nos is=49.5
  (x+2)+(x+4)+(x+6)+(x+8)/4=49.5
  4x+20/4=49.5
  4x+20=49.5*4
  4x+20=198
  4x=198-20
  4x=178=>x=178/4=>44.5
  =>x=44.5=>A=x+2=>44.5+2=46.5
  B=x+4=>44.5+4=48.5
  C=x+6=>44.5+6=50.5
  D=x+8=>44.5+8=52.5
  B*D=48.5*52.5=2546.25
• 11 years agoHelpfull: Yes(0) No(3)
• 
  (3) 2450
  
• 11 years agoHelpfull: Yes(0) No(4)
• 4a=192
  a=48
  b=49
  d=51
  49*51=2499
• 11 years agoHelpfull: Yes(0) No(0)
• (b+c)/2=49.5
  b=49, c=50
  this gives a=48 & d=51
  hence 49*51=2499
• 11 years agoHelpfull: Yes(0) No(0)
• (x+x+1+x+2+x+3)/4=49.5
  4x=192
  x=48;numbers are 48,49,50,51.therefore,49*50=2450
• 11 years agoHelpfull: Yes(0) No(1)
• Ans:-2450;
  A-48,B-49,C-50,D-51
  
• 8 years agoHelpfull: Yes(0) No(1)
• let x be the first number then , next three numbers will be x+1,x+2 and x+3
  given, (x+(x+1)+(x+2)+(x+3))/4=49.5
  on solving,
  x=48 thus B=49 and D=51
  B*D=2499
• 8 years agoHelpfull: Yes(0) No(0)
• 1) 2499
  The total sum is 198
  then sum of four consecutive no is x+(x+1)+(x+2)+(x+3)=x+6
  then we get x= 48 means
  the no.s are
  48, 49, 50 and 51
  then
  49*51=2499
• 5 years agoHelpfull: Yes(0) No(0)