In a number system the product of 44 and 11 is 2124. The
number 3111 of this system, when converted to the decimal number system,
becomes:
(a) 406
(b) 1086
(c) 213
(d) 691

• 691
  
  44*11= 484
  if 2124 is written in base n , then
  2n^3+ n^2+2n+4=484
  2n^3 + n^2 + 2n - 480 = 0
  solving it, we get n = 6 .
  
  3111 in base 6 = 3n^3 + n^2 + n + 1 = 3*216 + 36 + 6 + 1 = 691
• 11 years agoHelpfull: Yes(6) No(0)