in a company there are 2/6 java programmer, 1/2 programmer knows c++ and 1/5 programmer doesn't know

anything. then find ther fraction of programmers who knows both java and c++.

• 1/5 do not know anything so left programers are=4/5
  lex x persons know both so
  4/5=2/6+1/2-x
  so x=1/30
• 11 years agoHelpfull: Yes(57) No(1)
• ans is 1/30
• 11 years agoHelpfull: Yes(9) No(4)
• ans is 19/30
• 11 years agoHelpfull: Yes(9) No(11)
• n(java)=2/6
  n(c++)=1/2
  n(java intersection c++)=4/5
  now n(Java union c++)=n(java)+n(c++)-n(java intersects c++)=2/6+1/2-4/5=1/30
  
• 11 years agoHelpfull: Yes(7) No(1)
• fraction of programmers dont know=1/5
  only known programmers=1-1/5=4/5
  sets equaion
  n(AuB)=n(A)+n(B)-n(A^B)
  4/5=2/6+1/2-x
  solving
  x=1/30
• 11 years agoHelpfull: Yes(4) No(0)
• 2/6--> java==10/30
  1/2-->c++==15/30
  1/5-->none==6/30
  10/30+15/30+6/30=1
  31/30=1
  i.e, 1/30 ratio knw both java and c++
• 11 years agoHelpfull: Yes(3) No(3)
• how? plz explain
• 11 years agoHelpfull: Yes(1) No(1)
• ans is 9/30
  1-2/6-1/2-1/5
• 11 years agoHelpfull: Yes(1) No(7)
• =1/3 + 1/2 - 1/5
  =19/30..ans..
  
• 10 years agoHelpfull: Yes(0) No(1)