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Permutation and Combination
There are 4 married couples. How many couple groups are possible ? there should not be his or her spouse.
Read Solution (Total 7)
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- 12
- 15 years agoHelpfull: Yes(9) No(2)
- 9 couple groups. The problem is similar to arranging 1, 2, 3 and 4 in 4 places such that no number has either 1 as first number or 2 as second number or 3 as 3rd number or 4 as fourth number. All numbers satisfying this condition are 2143, 2341, 2413, 3142, 3412, 3421, 4123, 4312, 4321. There are 9 such numbers. So, there are 9 such groups possible.
- 15 years agoHelpfull: Yes(5) No(8)
- 16 possible
if H stands for Husband and W for Wife, and the numbers 1, 2, 3, and 4 label which couple the person is from, then the 16 possible teams are:
1) H1 H2 H3 H4
2) H1 H2 H3 W4
3) H1 H2 W3 H4
4) H1 H2 W3 W4
5) H1 W2 H3 H4
6) H1 W2 H3 W4
7) H1 W2 W3 H4
8) H1 W2 W3 W4
9) W1 H2 H3 H4
10) W1 H2 H3 W4
11) W1 H2 W3 H4
12) W1 H2 W3 W4
13) W1 W2 H3 H4
14) W1 W2 H3 W4
15) W1 W2 W3 H4
16) W1 W2 W3 W4 - 6 years agoHelpfull: Yes(3) No(0)
- 12
- 15 years agoHelpfull: Yes(2) No(2)
- 9
- 15 years agoHelpfull: Yes(1) No(2)
- 4P4 - (4C1 + 4C2 + 4C3 + 4C4) = 24 - (4 + 6 + 4 + 1) = 24 - 15 = 9 groups
- 15 years agoHelpfull: Yes(1) No(4)
- 15
combination of 1 couple=4C1=4
combination of 2 couple=4C2=6
combination of 3 couple=4C3=4
combination of 4 couple=4C4=1
total =15 - 11 years agoHelpfull: Yes(1) No(4)
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