The average of squares of first 11 consecutive even numbers is:
(a)184 (b)148 (c)186 (d)174

• 184
  
  Av will be
  (2^2+4^2+..........22^2)/11 = 4(1^2+2^2+......11^2)/11 = (4*11*12*23)/(6*11)= 184
  
  using formula
  sum of squares of first n natural numbers = n(n+1)(2n+1)/6
• 13 years agoHelpfull: Yes(13) No(8)
• 2(n+1)(2n+1)/3
  (2*12*23)/3
  =2*4*23
  =184
• 9 years agoHelpfull: Yes(0) No(0)