In a party 6 couples were present, 4 people are to be selected at random. Find the probability that exactly one couple is to be selected.

1) 32/33
2) 16/33
3) 35/66
4) 27/66

• out of 6 couple select 1:6c1 =6
  
  in remaining 5 couple (10 members), select 2:10c2..........in these 5 ways include a couple...........so 10c2-5
  
  total ways of selecting: 12c4
  
  so:6c1*(10c2-5)/12c4 =16/33
• 12 years agoHelpfull: Yes(0) No(0)
• 16/33
  6 ways to select a couple (2 persons)
  other 2 persons can be selected in 2*5C1*4C1= 2*5*4= 40 ways
  
  Total favourable ways = 6*40=240
  total possible combinations are 12C4 = 495
  probability that exactly one couple is to be selected = 240/495= 16/33
  
  
• 12 years agoHelpfull: Yes(0) No(0)