A jar contained a mixture of two liquids A and B in the ratio 4:1. When 10 litre of mixture was taken out and 10 Litre of liquid B was poured into the jar , this ratio becomes 2:3. The quantity of liquid A contained in jar initially was

1) 4 L
2) 8 L
3) 16 L
4) 40 L

• Ans 16L............
  Given ratio of liquid A & B = 4:1
  Let quantity of liquid B be x litres
  Therefore quantity of liquid A is 4x litres
  Total quantity in jar now is 5x litres
  Now 10L is taken out so jar has 5x-10 L
  quantity of liquid a is 4(5x-10)/5 = 4x-8 L (since ratio is still 4:5)
  quantity of liquid b is (5x-10)/5 = x-2 L (since ratio is still 4:5)
  Now 10L liquid b is added so quantity of liquid b is x-2 + 10=x+8 L
  Now the ratio becomes:
  (4x-8)/(x+8)=2/3
  This gives x=4L
  Hence initial quantity of a = 4x =16L
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