Three consecutive whole numbers are such that the square of the middle number is greater than the product of the

this is a property for number any three consecutive whole numbers ............

so , any three consecutive whole numbers can be the answer
13 years agoHelpfull: Yes(42) No(10)

It can be any set of three consecutive numbers.
If numbers are (x-1),x , (x+1)
then (x+1)*(x-1) = x^2-1 which is less than square of middle number by 1.
13 years agoHelpfull: Yes(15) No(5)
ans : 2n,2n+1,2n+2 where n = 1,2,3...
13 years agoHelpfull: Yes(8) No(5)
numbers are 2,3,4
3*3=4*2+1
middle number is 3
13 years agoHelpfull: Yes(7) No(13)
There is no unique solution
:
let x = the middle number
then
(x-1) = the 1st number
and

(x+1) = the 3rd number
:
x^2 = ((x-1)*(x+1)) + 1

x^2 = x^2 - 1 + 1
:
x^2 = x^2
Which means this is true for any 3 consecutive numbers even, -1, 0 +1
:
Try a few like; 142, 143, 144: 143^2 = 20449, 142*144 = 20448
10 years agoHelpfull: Yes(5) No(4)
2 or 3 (eg.123 or 234)
9 years agoHelpfull: Yes(1) No(0)
7 8 9 7*9=63 8*8=64
7 years agoHelpfull: Yes(1) No(0)
i think middle number is 1.
9 years agoHelpfull: Yes(0) No(0)
its says ..which number satisfy the following equation
(x^2) - 1 = (x -1)(x+1)
but this is a universal formulae... so answer can be any.

36-1 = 7*5
18^2 - 1 = 17*19
... so on
8 years agoHelpfull: Yes(0) No(0)
any three consecutive numbers
8 years agoHelpfull: Yes(0) No(0)
three consecutive numbers be 765
product = 7*5=35;
square= 6*6 = 36
therefore 36-35 =1.
6 years agoHelpfull: Yes(0) No(0)
It can be any set of three consecutive numbers.
If numbers are (x-1),x , (x+1) ,he told that square of x is differ by 1 to the product of residue numbers
then x^2=(x+1)(x-1)+1,so x can be any number
6 years agoHelpfull: Yes(0) No(0)

Three consecutive whole numbers are such that the square of the middle number is greater than the product of the other two by 1. Find the middle number.