MBA
Exam
Numerical Ability
Clocks and Calendars
Q--What is the maximum possible sum of the number of Tuesdays and Wednesdays in two consecutive years? 1) 208 2) 209 3) 210 4) 211 5) 212
Read Solution (Total 1)
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- there are three possibilities: 1) first year can be a leap year 2) second year can be a leap year 3) none of the two is a leap year
1) first year is a leap year: 52 weeks and 2 odd days: means 52*2 = 104 number of tues and wed for sure. Let the rem two odd days are tues and wed. now the second year will start from thurs and will complete its 52 weeks on thurs only, remaining 3 odd days are going to be fri, sat and sun.
so total number of tues and wed in 2nd year = 52*2 = 104
total number of tues and wed in 2 consecutive years = 104 + 2+ 104 = 210
Similarly check for other two cases and will get the same result. - 7 years agoHelpfull: Yes(0) No(0)
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