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There are 3 societies A, B, C. A Lent Tractors to B and C as many as they had
already. After some time B gave as many tractors to A and C as many as they have. After sometime C did the same thing.At the end of this transaction each one of them had 24.
Find the cars each originally had.This question was bit differently asked with the same thing.
Read Solution (Total 7)
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- ans from reverse a 24 b 24 c 24
before transaction a 12 b 12 c 48
before previous a 6 b 42 c 24
initially a 39 b 21 c 12 - 10 years agoHelpfull: Yes(23) No(7)
- A had 39, B had 21, C had 12
- 15 years agoHelpfull: Yes(12) No(21)
- please write correct question
- 10 years agoHelpfull: Yes(1) No(0)
- suppose initially each A,B,C has x,y,z number of cars.
when A lent to B and C
then B=2y
C=2z
similarly when B lent to A and C
then , A=2x
C=4z
similarly when C lent to A and B
then, A=4x
B=4y
since at last each one has 24 cars
so,for A, 4x=24
x=6
y=6
z=6
so each one has originally 6 cars... - 10 years agoHelpfull: Yes(1) No(3)
- A had 42, B had 6 and C had 24
- 10 years agoHelpfull: Yes(0) No(5)
- please explain the solution in detail...........
- 10 years agoHelpfull: Yes(0) No(0)
- 0...because everyone lent tractor and not the car...
- 8 years agoHelpfull: Yes(0) No(1)
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