What is the number of zeros at the end of the product of the numbers from 1 to 100?

• For finding zeros at the end of 100!,
  formula is 100/5+100/5^2 = 20+4=24
  because each factor of 5 contributes one zero (100/4), and 25's contribute 2 factors of 5 so we need to make sure we don't miss that extra 5's contribution (100/25).
  
• 13 years agoHelpfull: Yes(27) No(8)
• Multiplication by 10=11
  Multiplication by 5=11
  and 1*100=100=>2
  Adding we get '24'
• 13 years agoHelpfull: Yes(14) No(8)
• for 10!
  10/5 =2 zeroes
  for 100!
  100/5 + 100/25 + 100/125 = 20+4+0 = 24
  here denominator increases as 5 square , 5 cube and so on...
  as 125>100 then neglect it
  like wise for 200!
  200/5+ 200/25 + 200/125 +200/652 = 40+8+1+0 = 49
  dont consider decimal values
• 10 years agoHelpfull: Yes(4) No(0)
• 1*2*3*4*....*10...*20.....*100=_ _ _ ......_ _ 00000000000
  11 zeroes
• 13 years agoHelpfull: Yes(3) No(24)
• @Sanjeev
  sir you counted multiplication by =11 which includes 100 also...
  then how we recount 1*100 again sir?
• 12 years agoHelpfull: Yes(3) No(2)