Peter and Paul ate two friends. The sum of their ages is 35 years. Peter is twice as old as Paul was when Peter was as old as Paul is now. What is the preset ate of Peter?

• let pauls age be 'a' and peters be 'e'
  e+a=35 (given)
  e=35-a ------eq1
  when peter was as old as paul that is when peter's age was 'a' i.e e-(e-a) [for example if e was 9 and a was 5, e-a is 4,9-4=5 so e-(e-a)]
  pauls age was a-(e-a) =2a-e
  now peters age is e=2(2a-e)
  e=4a-2e
  3e=4a
  3(35-a)=4a
  105-3a=4a
  a=15
  hence e=20
• 13 years agoHelpfull: Yes(12) No(0)
• ans is present age of peter is 21..
  let paul's age be x and peter be y..
  according to the problem...x+y=35..and also said that peter's age is twice that of paul when peter's age was equal to paul's present age so when peter was x paul's age should be x/2..now paul's present age is x so peter's age was double that of paul x/2 years back..so now peter's present age is x+x/2=3x/2..now substitute y=3x/2...there fore x+3x/2=35..x=14 that is paul's age..there fore peter's age is 21....
• 13 years agoHelpfull: Yes(6) No(2)
• Let pauls age be 'a' and peters be 'e'
  e+a=35 (given)
  e=35-a ------eq1
  when peter was as old as paul that is when peter's age was 'a' i.e e-(e-a) [for example if e was 9 and a was 5, e-a is 4,9-4=5 so e-(e-a)]
  pauls age was a-(e-a) =2a-e
  now peters age is e=2(2a-e)
  e=4a-2e
  3e=4a
  3(35-a)=4a
  105-3a=4a
  a=15
  Hence e=20
• 13 years agoHelpfull: Yes(1) No(0)
• 20 is the answer....
  Present. Past
  Peter. 2x. 35-2x
  Paul. 35-2x. x
  Now diff of their pres n past ages r equal
  We get x as 10. So 2x is 20.....
• 13 years agoHelpfull: Yes(0) No(1)