Three identical cones with base radius r are placed on their bases such that each is touching the other two.the radius of the circle passing through their vertices is

1) r/(root3)
2) 2r
3) 2r/(root3)
4) (root 3) r/2

• The centers when joined form an equilateral triangle with side 2r. The circumcircle of this triangle will be our required circle. The circumradius of this circle will be 2r/(root3) = 1.155r > r.
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