What is the last digit of 6^567 + 8^1009 + 14^147?

1) 0
2) 2
3) 4
4) 8

• 6^anything gives last digit as 6 ,
  Coming to 14^ anything we are concern abt last digit so let's check with 4^1 =4 , 4^2=16 ,4^3=64 hence period is 2 so when 147/2 gives 4 as a last digit . 8 as last digit it has (8 ,4,2,6) when powers of 8 raised exponentially 8 has period 4 so it gives 1009/4 which leaves reminder 1 (which is actually 1st digit in cycle (8)) so two digits are 6+4+8 = 18 from that last digit is 8
• 7 years agoHelpfull: Yes(0) No(0)