16 Men complete one-fourth of a work in 12 days.find the no. Of men required to complete the remaining work in 12 days

• Use (m1×d1)/(w1)= (m2×d2) /(w2) formula. Let total m men are required.Put m1=16, d1=12,w1= 1/4 , d2 =12, w2=3/4. After putting values, we get (16×12)/(1/4)=(m×12)/(3/4) and after solving we get m=48 so total 48 men are required. So additional men will be (48-16)= 32.
• 7 years agoHelpfull: Yes(6) No(1)
• 48
  
  As 3/4 of the work is left, which is 3 times the completed work in 12 days
  So, in the 12 days, men required=3*existing men=3*16=48
• 9 years agoHelpfull: Yes(4) No(5)
• 1/4 work done in 12 days require = 16 men.
  3/4 work done in 12 days require = (16×3) = 48 - [Option D]
• 6 years agoHelpfull: Yes(0) No(3)
• `1/4 : 1 = 16 : 16 + x => 16/(16 + x)`
  
  `= 1/4`
  
  `:. 16 + x = 64 => x = 48`
• 6 years agoHelpfull: Yes(0) No(2)
• Use (m1*d1)/ (w1) = (m2*d2)/ (w2) formula.
  Put m1 = 16, d1 = 12, w1= 1/4, d2 = 12, w2 = 3/4.
  Hence (16*12)/ (1/4) = (m*12)/(3/4) = 48
  Additional men required to complete the work = (48 - 16) = 32.
• 5 years agoHelpfull: Yes(0) No(2)