A speaks truth 70% of the time; B speaks truth 80% of the time. What is the probability that both are contradicting each other?

• P(A)=.7
  P(B)=.8
  the probabililty to contradict each other is...
  A tells truth n B tells lie
  B tells truth n A tells lie
  means
  (0.7*0.2)+(0.3*0.8)=0.38
• 13 years agoHelpfull: Yes(10) No(0)
• p(a)=0.7
  p(b)==0.8
  as both are independent events,the pro to contradict each other is:
  a)a tells truth while b tells falsei.e.(0.7*0.2)+
  b)a tells false while b tells truth i.e.(0.3*0.8)
  results 0.38
  
• 13 years agoHelpfull: Yes(4) No(1)
• (.7)*(.2)+(.3)*(.8)=.38
  38% probability is there
• 13 years agoHelpfull: Yes(4) No(1)
• p(C)=p(A)+p(B)-2*p(A intrsctn B)
  =.7+.8-2*.7*.8 =.38
  38%
• 13 years agoHelpfull: Yes(3) No(2)