find the sum of the geometric series
6
[SUM] 2^n
n=1


n=1 2^1=2
n=2 2^2=4
n=3 2^3=8
n=4 2^4=16
n=5 2^5=32
n=6 2^6=64
2+4+8+16+32+64= 126

am I doing this correctly?