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Numerical Ability
Probability
70 students are required to paint a picture. 52 use green color and some children use red, 38 students use both the colors. How many students use red color?
Read Solution (Total 18)
-
- 70 = red +green -both
Red = 70-green+both = 70-52+38=56 - 13 years agoHelpfull: Yes(46) No(1)
- 52-38=14---uses only green color
70-52=18---uses only red color
38 students uses both colo
38+18=56 uses red color - 13 years agoHelpfull: Yes(14) No(4)
- 52-38=14---uses only green color
70-52=18---uses only red color
38 students uses both color
38+18=56 uses red color - 13 years agoHelpfull: Yes(6) No(2)
- 56 use red color.
since
70 = 52 + x - 38
or, x = 56 - 13 years agoHelpfull: Yes(5) No(0)
- it s more easy if u apply venn diagram
sol :--- 38 = r+g.,, g =52... therefore only g=52-38=14 so red = only red + (red +green) = total - only green== 70-14=56 use red color.. :) :P - 13 years agoHelpfull: Yes(3) No(0)
- u= p(green)+p(red)-p(green ^red); p(red)=70+38-52=56;
- 13 years agoHelpfull: Yes(2) No(0)
- 18+38=56 used red
- 13 years agoHelpfull: Yes(2) No(0)
- n(A U B) = n(A) + n(B) - n(A instersection B)
n(A U B)=70
n(A)= 52
n(A instersection B) = 38
n(B)= ?
70=52+x-38
x=56 - 10 years agoHelpfull: Yes(1) No(0)
- it can be solved by using the simple probability formula
P(AUB)=P(A)+P(B)-P(A^B)
52+x-38=70
x=56 - 10 years agoHelpfull: Yes(1) No(0)
- 70 = 52 + x - 38
x = 56 ans
- 9 years agoHelpfull: Yes(1) No(0)
- total 72
52 using green color
38 both color
so 72-((52-38)+38)=20 - 13 years agoHelpfull: Yes(0) No(4)
- 18
70-52=18 - 9 years agoHelpfull: Yes(0) No(6)
- 18 students
- 8 years agoHelpfull: Yes(0) No(1)
- answer is 56.
70-52+38=56 children uses red color out of 70 - 7 years agoHelpfull: Yes(0) No(0)
- n(G)+n(R)-n(G+R)
- 7 years agoHelpfull: Yes(0) No(0)
- (52+x)/2=38
52+x=76
x=24 - 5 years agoHelpfull: Yes(0) No(0)
- A=52
b=38
and p(aub)=70
i.e by formula
p(AUB)=P(A)+p(b)-P(AUB)
=70-52+38
=56 - 5 years agoHelpfull: Yes(0) No(0)
- Total student = red+green-both
70 = x +52 -38
x=56
Therefore, 56 use red colour - 1 year agoHelpfull: Yes(0) No(0)
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