Find the sum pf all three digit number that give a remainder of 4 when they are divided by 5..please explain the procedure....

1) 98270
2) 99270
3) 102090
4) 90270

• 99270
  
  sum of numbers 5x+4
  where
  x=20,21..199
  
  sum = 5*(20+21+..199)+4*180 = 5*(180/2)*(10+199) + 720 = 99270
• 12 years agoHelpfull: Yes(0) No(0)