P can finish a work in 18 days. Q can finish the same work in 15 days. Q worked for 10 days and left the job. how many days does P alone need to finish the remaining work?

Options
1) 8
2) 5
3) 4
4) 6

• A simple way to solve this kind of problems :-
  Suppose p can do it in x days and we already know dat q has worked for 10 days so use this formula -
  X/18+10/15=1
  Solving this we get x=6 which is required ans....
• 9 years agoHelpfull: Yes(20) No(0)
• q's one day work=1/15
  q's 10 day work=10/15=2/3
  remaining work=1/3
  p's one day work=1/18
  so days needed=6
  i.e. answer=4)
• 9 years agoHelpfull: Yes(12) No(9)
• ans is 6 days
  lets assume for P
  1 day = 1 unit work
  18 day = 18 unit
  1 day = 6 hour
  then for Q
  he can work same amount of work in 15 days, so
  15 days = 18 unit
  1 day = 18/15 = 6/5;
  10 days = 10*6/5 = 12 unit ( 6 unit work remaining)
  now p has to work alone for 6 day = 6unit
• 9 years agoHelpfull: Yes(3) No(0)
• In one day P works (100/18)% work
  and Q does (100/15)% work
  In 10 days Q does (200/3)% work so the remaining (100/3)% work is done by P in 6 days
  
• 9 years agoHelpfull: Yes(1) No(1)
• For this type of problem its always preferred to take total work as the l.c.m. of the no. of days P can finish the work and no. of days Q can finish the work so,
  Let total work = 90 units
  Then, In one day P does 5 units of work and Q does 6 units of work
  Now Q worked for 10 days so work done = 10*6 = 60 units of work
  Left work = 90-60= 30 units
  So P will take = 30/5= 6 days to do the work
  so ans 4) 6
• 9 years agoHelpfull: Yes(1) No(0)
• p 's 1 day work is 1/18 and q's 1 day work is 1/15
  both are working together then their one day work is 1/18+1/15=11/90
  
  q work for 10 days then 10 days they are working together then remaining work which is left for p
  =1-(11/90*10)=2/9
  now using basic rule:
  1/18 work done in 1 day
  then 2/9 work is 18*2/9=4
  
  
• 9 years agoHelpfull: Yes(1) No(0)
• Ans: 4) 6
  
  
  
  
  
  
  
  
  
• 9 years agoHelpfull: Yes(0) No(0)
• Q'S 10 DAYS WORK =10/15=2/3
  THEN REST OF D WRK =1/3
  P CMPLTED D REMAINING WORK IN 18/3 DAYS MEANS 6 DAYS
• 9 years agoHelpfull: Yes(0) No(0)
• ans = 6
  ( 1 - person who left the work / )*the person who works till end from starting
  (1-10/15)*18
  = 6
• 9 years agoHelpfull: Yes(0) No(0)
• ((x-n)/x)*Y
  where x is the work done by Q
  Y is the work done by P
  n days Q has worked
  solution would be
  ((15-10)/15)*18 =6 days
• 9 years agoHelpfull: Yes(0) No(0)
• B's 10 day's work = (1/15x 10) = 2/3 .
  Remaining work = ( 1 - 2/3 ) = 1/3 .
  Now, 1/18 work is done by A in 1 day.
  Therefore 1/3 work is done by A in ( 18 x 1/3 ) = 6 days.
• 9 years agoHelpfull: Yes(0) No(0)
• ANSWER IS 4) 6
  
• 9 years agoHelpfull: Yes(0) No(0)
• ans is 4 not 6
  
• 9 years agoHelpfull: Yes(0) No(1)
• Answer is 6
  Coz, B's 10 day work = (1/15*10)=2/3
  So remaining work =(1-2/3)=1/3
  A's one day work = 1/18
  therefore 1/3 work's is done by A in (18*1/3) = 6days
• 9 years agoHelpfull: Yes(0) No(0)
• 4)6.
  take the lcm of 18 and 15=90.
  90/18=5 unit per day by p.
  90/15=6 unit per day by q.
  total unit=90.
  in 10 days q will work=10*6=60 unit
  remaining work=90-60=30
  so p will do the work in 30/5 days=6 days
• 9 years agoHelpfull: Yes(0) No(0)
• The answer is 4
  work done by Q in ten days = 1/15*10 = 2/3
  Remaining work 1-2/3 = 1/3
  therefore if P's one day work = 1/18 then P can finish 1/3 work in 1/3*18 = 6days
• 9 years agoHelpfull: Yes(0) No(0)
• P can finish desired work in 18 days
  Q can finish desired work in 15 days
  Total work= 90 unit (LCM of 18 & 15)
  P does 5 unit of work/day and Q does it 6 unit/day
  Now, after 10 days ,amount of work done=6*10= 60 unit
  Remaining work=90-60= 30 unit
  Hence ,reuired no. of day in which P can finish the reamaining work=30/5=6 days Answer
  
  After 10 days , amount of work done= 10
• 9 years agoHelpfull: Yes(0) No(0)
• is it really a elitmus qus..its quite easy..
• 9 years agoHelpfull: Yes(0) No(0)
• P can work for 5 units per day
  Q can work for 6 units per day
  so Q work for 10 days = 6*10= 60 units of work done remaining work 30 units
  P does it in 30/5 = 6 days
• 9 years agoHelpfull: Yes(0) No(0)
• q '1 day work=1/15 so, q 10 day work=10/15
  work left=1-10/15=1/3
  1/18 work p finish in =1 day so,
  1/3 work p finish in=6 day .ans=option(4)
• 7 years agoHelpfull: Yes(0) No(0)