MBA
Exam
Numerical Ability
Time Distance and Speed
Two trains start simultaneously from P & Q towards Q & P resp at 8 am. They cross each other at 12 noon. Train starting from Q, thereafter takes 6 hrs to reach P. On a particular day, the train starting from P, reduced its speed and arrived at Q, 200 min late. At what time did the trains cross each other on that day? 1) 1PM 2) 1:30PM 3) 2PM 4) None
Read Solution (Total 2)
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- Given that Q takes 4 hrs to meet train which is starting from P and Takes 6 hrs to reach P.
Hence we can say that P has traveled 2/3rd of the distance. It means train starting from P has traveled 1/3rd of the Distance in 4 hrs.
Total Time taken by Train Starting from P= 4*3=12 hrs.
Now the second condition is given which is P reduces its speed and reaches 200 min late.
Now, Total time taken by P=12 hrs + 200 min= 920 minutes .
The other train still takes 360 min
So their speed ratio is 920:360=23:9
So the faster one travels 23/32 distance when they meet which will take 23*360*60/32 sec=15525 secs= 4 hr 18 min 45 secs
Which is 12:18:45
OPTION (4) - 9 years agoHelpfull: Yes(0) No(1)
- answer is 1pm
- 5 years agoHelpfull: Yes(0) No(0)
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