MBA Exam Logical Reasoning Cryptography

what is the distance in cm between two parallel chords of length 32 and 24cm in a circle of radius 20cm maaf karo eazzzy question ke liye.. i have started geometry finally

1) 1
2) 4
3) 28
4) 4 or 28

Read Solution (Total 2)

There are 2 possibilities :

Both chords on opposite side of the centre.

Both side on the same side from the centre.

Opposite side:

Perpendicular from the centre to the chord, bisects the chord.

Hence PB = 12 and QA = 16.

Now apply Pythagoras theorem.

OP2 = OB2 - PB2 = 400 – 144 = 256. OP = 16.

OQ2 = OA2 - QA2 = 400 – 256 = 144. OQ = 12.

Hence, the distance is sum of OP and OQ is 28.

Same side :

We get OP as 16 and OQ as 12 (explained above).

Since they are on the same side, the distance between them is 4. (16 – 12)
10 years agoHelpfull: Yes(23) No(6)

ans:=4 or 28
10 years agoHelpfull: Yes(2) No(7)

MBA Other Question

Givena trapezium ABCD with AB || CD , CD = 2AB and DB perpendicular to BC.Let E be the intersection of lines DA and CB, and F be the midpoint ofDC. Which among the following is not true?

1) ABFD is a rhombus
2) Triangle CDE is isosceles
3) If AF and BD meet at G, and GE and AB meet at H then the line DH bisects segment EB
4) At least two of the above
5) None of the above
If in any decreasing arithmetic progression, sum of all its terms, except for the first term, is equal to -36, the sum of its terms, except for the last term, is zero, and the difference of the tenth and sixth term is equal to -16, then what will be the first term of this series?

1) 16
2) 20
3) -16
4) -20
5) -24