a goods train travels a station at a certain time and at fixed speed. after 6hrs another train leaves the same station and move in same direction of uniform speed of 90kmph. the train catches up the good train in 4hrs. find the speed of the good train.

• let the speed of goods train be x
  dist covered by goods train in 10hrs (4+6)= dist covered by other train 4 hrs
  10x=4*90
  x=36kmph
• 9 years agoHelpfull: Yes(10) No(0)
• Faster train covers total dis.. in 4 hour
  Total dis=90*4=360
  Goods train takes 10 hours
  So speed of goods train =360/10=36 ans
• 9 years agoHelpfull: Yes(2) No(0)
• Explanation required plz..
• 9 years agoHelpfull: Yes(1) No(0)
• distance covered in 10 hrs =distance in 4 hrs
  therefore 10x=S*T
  =10x=90*4=360
  X=36 km/hrs
• 9 years agoHelpfull: Yes(1) No(0)
• Let speed of the goods train be y km/h. Distance travelled by goods train in 6 hours = 6 * y. that is 6y.
  now relative speed of the new train = 90-y.
  6y distance is travelled by new train at 90-y speed in 4 hours
  6y/90-y=4
  y=36km/h
• 9 years agoHelpfull: Yes(1) No(0)
• 36 kms is the answeer
  
• 9 years agoHelpfull: Yes(0) No(0)
• ans:36kmph..
• 9 years agoHelpfull: Yes(0) No(0)
• ans: 36kmph
  
• 9 years agoHelpfull: Yes(0) No(0)
• let the speed of goods train be x
  distance travel in 6 hr with x speed=6x
  4=((6x/(90-x))
  so x=36km/h
• 9 years agoHelpfull: Yes(0) No(1)
• Good trains travels for 6 hrs
  After 6 hrs express train leaves same station and reaches to good train in 4 hrs.
  so total time covered by good train is 10 hrs
  Distance covered by express train in 4 hrs is 90 * 4 = 360 km
  And Good train also covered same distance in 10 hrs
  so, s=360/10
  s=36 kmph
• 5 years agoHelpfull: Yes(0) No(0)