A vendor sells 1 apple for 1 penny, 2 grapes for 1 penny, 3 bananas for 1 penny. A man spends 7 penny and gives equal amount of fruits to each of his three daughters. What is the possible number of fruits each daughter gets?

• He buys 3 banana for 1 penny.
  6 grapes for 3 pennies.
  3 apples for 3 pennies.
  and then gives 1 banana , 2 grapes and 1 apple to each daughter.
• 13 years agoHelpfull: Yes(13) No(1)
• A vendor sells 1 apple for 1 penny, 2 grapes for 1 penny, 3 bananas for 1 penny. A man spends 7 penny and gives equal amount of fruits to each of his three daughters.
  
  He buys 3 banana for 1 penny.
  6 grapes for 3 pennies.
  3 apples for 3 pennies.
  and then gives 1 banana , 2 grapes and 1 apple to each daughter.
• 13 years agoHelpfull: Yes(8) No(1)
• a man buy 3 apples for 3 penny, 6 grapes for 3 penny, and 3 bananas for 1 penny.
  he distribute 1 apple per head, and 2 grapes per head, and finally 1 bananas per head. the problem solved
• 13 years agoHelpfull: Yes(4) No(0)
• for 7 penny he can get following amount of fruits to distribute it to her 3 daughters equally.
  1. 21 bananas = 21
  2. 15 bananas + 2 grapes + 1 apple = 18
  3. 12 bananas + 3 apple = 15
  4. 9 bananas + 4 grapes + 2 apple = 15
  5. 6 bananas + 2 grapes + 4 apple = 12
  6. 3 bananas + 12 grapes = 15
  7. 3 bananas + 6 apple = 9
  8. 4 grapes + 5 apple = 9
  9. 10 grapes + 2 apple = 12
  So each daughters get either 3,4,5,6 or 7 fruits
• 13 years agoHelpfull: Yes(0) No(8)