two jets are traveling towards each other and are 4000 km apart. The rate of one jet is 100 km/h faster than the rate of the other. if the jets pass each other after 2.5 hours, what is the rate of the faster jet?

• distance=Relative speed* time
  4000=(v1 +v2)*2.5
  v1 +v2=800 ........(i)
  According to question
  v1 -v2=100........(ii)
  Adding both eq (i) and (ii)
  2v1 = 900
  v1=450 Km/h
  v2=450-100=350 Km/h
  01
• 8 years agoHelpfull: Yes(0) No(0)