exam
Maths Puzzle
Numerical Ability
xy + 3z + y =
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Help!!!
Can you show that, given two equations y=m1x+c1 and y=m2x+c2, where c1=c2, that there will be at least one solution no matter what m1 and m2 are. Interpret the reults on
please help me solve these problems:
3/4 (7k - 5)=12
5(3-x)< 3(x-3)
3x + 2 < 5