MBA Exam

A point is selected at random from the four quadrants of the XY plane. For each of the points selected, all possible lines are drawn which pass through the point and only two quadrants. What is the maximum number of points at which these lines can intersect?

1) 55
2) 41
3) 29
4) 19

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MBA Other Question

60/(u-v) + 100/(u+v) = 875/(u-v) + 175(u+v) = 12faster way to solve this..we are suppose to find u?

1) I know it lemme post the approach
2) No idea
option A is 40 not 45.I don't have answer. Please provide your approach.

1) 45
2) 90
3) 120
4) 150