when fair coin is tossed 9 times find the probability of getting head at least once.1)1/512 2)511/512 3)9/512 4)503/512.

• 1-1/2^9= 1-1/512 = 511/512
• 13 years agoHelpfull: Yes(6) No(1)
• 1-1/2^9= 1-1/512 = 511/512
• 13 years agoHelpfull: Yes(3) No(0)
• option 2 is correct 511/512 . because 9 time they tossed then we calculate head not appears any time and after that at least one time .
• 13 years agoHelpfull: Yes(2) No(1)
• 511/512
  prob of atleast one head = 1- prob. of no head
  = 1- 1/512( TTTTTTTTT is the only way with out head )
  = 511/512
• 13 years agoHelpfull: Yes(2) No(1)
• so there are 512 chances and among them getting head atleast once is 1-1/512=511/512
  
• 13 years agoHelpfull: Yes(1) No(0)