MBA Exam

Five different integral but unknown weights are there. Sum of weights taken two at a time in kgs are 122,124,125,126,127,128,129,130,132,133. Calculate the third weight!!!!

1) 64
2) 63
3) 65
4) 66

Read Solution (Total 1)

x1+x2=122
x2+x3=124
.....
.....similarly
x4+x5=133
sum all the 10 equations....
then 4(x1+x2+x3+x4+x5)=1276
x1+x2+x3+x4+x5=1276/4=319
then 122+x3+133=319
x3=319-(122+133)=319-255=46
so 3rd weight=64
11 years agoHelpfull: Yes(0) No(0)

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