Find the term next in series..

1,1/2,3/2,2,5,1/3,16/3,15,12,1/4,25/4,?

• [1,1/2,3/2,2],[5,1/3/16/3,15],[12,1/4,25/4,x]
  1+1/2=3/2......1/1/2=2
  5+1/3=16/3.....5/1/3=15
  12+1/4=25/4....12/1/4=48(Ans)
• 9 years agoHelpfull: Yes(41) No(44)
• [1,1/2,3/2,2],[5,1/3,16/3,15],[12,1/4,25/4]
  1+[3/2-1/2]*1=1+1*1=2
  5+[16/3-1/3]*2=5+15/3*2=5+5*2=5+10=15
  12+[25/4-1/4]*3=12+24/4*3=12+6*3=12+18=30
  ans:30
• 9 years agoHelpfull: Yes(23) No(9)
• 
  1+[(1/2-3/2)*1]=1+1=2
  5+[(1/3-16/3)*2]=5+10=15
  12+[(1/4-25/4)*3]=12+18=30
• 9 years agoHelpfull: Yes(13) No(4)
• 1*2= 2
  5*3=15
  12*4=48
  ans) 48
  
• 9 years agoHelpfull: Yes(12) No(4)
• first divide into three parts
  1,1/2,3/2,5........5,1/3,16/3,15...........12,1/4,25/4,????
  1,1/2,3/2,2 see first 1 digit and multiply with denominator and that is the result
  First :::::;;;;1*2=2
  5,1/3,16/3,15 Second:::::5*3=15
  12.1/4,25/4,???? Third::;;;::::12*4=48
  
• 9 years agoHelpfull: Yes(7) No(2)
• 48 is the answer
  
• 9 years agoHelpfull: Yes(1) No(1)
• multiply the first number with the denominator to get the fourth number
  
  1,1/2,3/2,2 =1*2 =2
  
  5,1/3,16/3,15 = 5*3 =15
  
  12,1/4,25/4 = 12*4 = 48ans
• 9 years agoHelpfull: Yes(1) No(1)
• 1+[(1/2-3/2)*1]=1+1=2
  5+[(1/3-16/3)*2]=5+10=15
  12+[(1/4-25/4)*3]=12+18=30
• 9 years agoHelpfull: Yes(1) No(2)
• Nagalakshmi can you expand your answer?
• 9 years agoHelpfull: Yes(0) No(2)
• Please explain the solution of this question
• 9 years agoHelpfull: Yes(0) No(2)
• (1 1/2 3/2 2) (5 1/3 16/3 15) (12 1/4 25/4 ?)
  
  1+1/2= 3/2;
  1/ 1/2= 2;
  
  5+1/3= 16/3;
  5/ 1/3= 15;
  
  12+ 1/4= 25/4;
  12/ 1/4= 48;ans
• 7 years agoHelpfull: Yes(0) No(1)