a football player kicks the football from 2ft above the ground .the path of the ball is modeled by:h(d)=-0.015d^2=1.8d=c if the ball is not caught .how far does it travel before

• The c-value is equal to 2 because the starting height is 2 ft. So the new equation is h(d) = -0.015d^2 + 1.8d + 2. Then, set the equation equal to 0 because if the ball is not caught, the y-value is 0 when it hits the ground. To solve for d, the distance the ball traveled, use the quadratic formula. The a-value is -0.015, the b-value is 1.8, and the c-value is 2. When these values are substituted into the quadratic formula, the first steps is: x = (-1.8 ± √(1.8^2 - 4(-0.015*2))) / -0.03. When simplified, the two results are -1.101009267 and 121.1010093. -1.101009267 is rejected because the distance traveled cannot be negative. The final answer is 121.1010093 feet.
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