if (x + 1/x)^2= 3 find x^72+x^66+x^54+x^36+x^24+x^6+1 plz explain also...

1) 1
2) 2
3) 3
4) 4

• x^2 + 1/x^2 + 2 = 3
  
  so x^2 + 1/x^2 = 1
  
  or x^4 + 1 = x^2
  
  or x^4 - x^2 + 1 = 0
  
  or x ^6 + 1 = 0 ( multiplying by x^2 + 1)
  
  x = (-1)^1/6
  
  putting this value of x in above equation
  
  (-1)^12 + (-1)^11 + (-1)^9 + (-1) ^6 + (-1) ^4 + (-1)^1 + 1
  = 1+(-1) + (-1) + 1 + 1 + (-1) + 1 = 4-3 = 1
• 10 years agoHelpfull: Yes(1) No(2)