MBA
Exam
if (x + 1/x)^2= 3 find x^72+x^66+x^54+x^36+x^24+x^6+1 plz explain also... 1) 1 2) 2 3) 3 4) 4
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- x^2 + 1/x^2 + 2 = 3
so x^2 + 1/x^2 = 1
or x^4 + 1 = x^2
or x^4 - x^2 + 1 = 0
or x ^6 + 1 = 0 ( multiplying by x^2 + 1)
x = (-1)^1/6
putting this value of x in above equation
(-1)^12 + (-1)^11 + (-1)^9 + (-1) ^6 + (-1) ^4 + (-1)^1 + 1
= 1+(-1) + (-1) + 1 + 1 + (-1) + 1 = 4-3 = 1 - 11 years agoHelpfull: Yes(1) No(2)
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