A and B can finish a piece of work in15 days. A and C can take 2 days more than B and C take to finish the same piece of work. The three together can finish the work in 8 days. In how many days could each do the work by himself?

• a+b=15days 1 d=1/15
  a+c=b+c+2
  a+b+c=8 1 d=1/8
  c=1/8-1/15=7/120
  a+c=x
  b+c=x-2 1d=1/(x-2) b= 1/(x-2)-7/120
  b=
  1/8-1/x=1/(x-2)-7/120
  
  
• 9 years agoHelpfull: Yes(0) No(4)
• a+b+c=8, a+b=15,
  Assume b+c=x, c+a=x+2,
  so 2(15*x*(x+2))/15x +15x+30+x^2+2x=8
  => 11x^2-98x-120=0.
  x=10,-12/11.avoid negative value .so x=10.
  so b+c=10, c+a=12 a=(a+b+c)-(b+c)=8*10/10-8=40 days
  
  similarly b=40 and c=120/7
• 9 years agoHelpfull: Yes(0) No(4)