Elitmus
Exam
Logical Reasoning
Cryptography
ZQW
WXC
__________
XAZX
ACDR
EAEC
___________
WRCQcX
Read Solution (Total 8)
-
- Its very simple one cryp.
From the first column we can find E+1=W.
use this hind to solve ZQW*W=EAEC.
now with the help of heat n trial put different value of w and corresponding value of e to check the above expression.
put w cant be 1 as W= E+1. so least value of w will be 2.
check for w=2 and E=1.
it will not satisfy as we cant get 1 at unit place when u will multiply ny no wid 2 when there is no carry also.( u can visualize this on paper)
now put next higher value for W. i.e- 3 and E=2
this value will be satisfied with Q=4 and Z=8.
from this product u vll obtain the value of C ( as ZQW*W=EAEC).
ie. C=9
put C=9 and multiply ZQW*C=XAZX.
from here obtain the value of X=7.
and similarly as above use the value of X to solve this crypt.
result is:
8 4 3
* 3 7 9
-------------
7 5 8 7
5 9 0 1
2 5 2 9
-----------------
3 1 9 4 9 7 - 9 years agoHelpfull: Yes(13) No(0)
- ******843
******379
-----------------
7587
5901*
2529**
--------------------
319497 - 9 years agoHelpfull: Yes(5) No(0)
- 8 4 3
* 3 7 9
------------------------
7 5 8 7
5 9 0 1
2 5 2 9
---------------------
3 1 9 4 9 7
---------------------
Initially substitute the values of x from 1 thn 2,3....finally found the value of x as 7
Then the problem becomes easy...find the remaining values..dats it - 9 years agoHelpfull: Yes(1) No(0)
- Ans :843*379
- 9 years agoHelpfull: Yes(1) No(0)
- please Explain dude need explanation or give some hint how to sole
- 9 years agoHelpfull: Yes(0) No(0)
- 843
379
7587
5901
2529
319497
- 9 years agoHelpfull: Yes(0) No(0)
- first do trail and hit method by substituting the value of w = 1 and thn 2 and 3
as E = w -1 and proceed by verifying every time
- 9 years agoHelpfull: Yes(0) No(0)
- hint zqw
* w
------------
eaec so from 2,3,4........... 9 any w*w would be either one of the following 4/9/6/5 in qst w*w=c (third row) so do hi and trial and find the value of zqw*w=eaec...........
ans is 843
* 379
----------------
7587
5901
----------------------
319497 (ans)
2529 - 9 years agoHelpfull: Yes(0) No(0)
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