exam
Exam
Numerical Ability
if a+b+c=0 then a^3+b^3+c^3/abc=?
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formula is, if a+b+c=0 then, a^3+b^3+c^3 = 3abc
so, a^3+b^3+c^3/abc = 3abc/abc = 3
9 years ago
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