a manufacturing company has 15% cobalt ,25% led and 60% of copper. if 5kg of led is used in a mixture how much copper we need to use

• Check only ratio for quick solve. 15:25:60=3:5:12 . here 5kg for 25% led so 12kg for60%copper and 3kg for 15% cobalt. Nothing change in rstio so direct ans 12kg. Quick ans in one min
• 9 years agoHelpfull: Yes(29) No(0)
• 25%=5kg
  100%=20kg
  60% of 20 kg= 12kg
  12 kg.....
• 9 years agoHelpfull: Yes(26) No(0)
• 5 Kg of led = 25% of the mixture
  so Total Mixture(100%) is 20 Kg
  Now copper used for 20 kg mixture is : 20 * (60/100) = 12 Kg
• 9 years agoHelpfull: Yes(6) No(0)
• if we consider total mixture = X kg
  led = 5kg
  (25/100)*X = 5
  X = 20kg
  so the amount of copper is =>
  (60/100)*20 = 12Kg
• 9 years agoHelpfull: Yes(6) No(0)
• 25%=5kg
  60%=?
  ?=(60*5)/25=12kg
• 9 years agoHelpfull: Yes(2) No(0)
• in mixture total total led is used=5/25*100=20kg...... and
  60% of 20 kg is copper
  so 20*60/100=12kg copper is used..............
• 9 years agoHelpfull: Yes(1) No(0)
• cost od 5% is 1 then 60% cost will be= 60/5=12 kg copper
• 7 years agoHelpfull: Yes(0) No(0)