Average of 3 numbers ABC is given as 48. Average of A,B,C,D is 46. Its given that E is having 3 more than D, then Average of B,C,D,E is 45. What is the score of A?

• A=47
  
  average A+B+C= 48; A+B+C=3*48=144;
  average A+B+C + D= 46; A+B+C+D =4*46=184;
  D=40; GIVEN E=D+3=40+3=43;
  B+C+D+E=45*4= B+C+40+43=45*4
  B+C=180-40-43
  B+C=97
  A+B+C=144
  A+97=144
  A=47
  
• 9 years agoHelpfull: Yes(4) No(1)
• A+B+C=48*3=144;
  A+B+C+D=46*4=184;
  B+C+D+E=40*4=160;
  E=3+D;
  
  A+B+C+D=184
  144+D=184
  D=40;
  
  B+C+D+E=160
  B+C+2D+3=160
  B+C+2*40+3=160
  B+C=77;
  
  
  A+B+C=144
  A=144-77
  A=67;
  
• 8 years agoHelpfull: Yes(0) No(3)
• A+b+c=48×3=144
  A+b+c+d=46×4=184
  Solving above equation we get d=40,so e=43
  Now from next equation b+c+d+e=45×4=180
  Now substitute d and e value we get b+c value
  Substitue b+c value in first equation the we a value as 47
• 5 years agoHelpfull: Yes(0) No(0)