Elitmus
Exam
Logical Reasoning
Cryptography
MXS
*ANN
-------------
XKNM
XKNM*
WXZW**
-------------
AWEKXM
Read Solution (Total 4)
-
- X must be greater than 4 since carry is generated, i.e, W+1=A.
now apply hit n trial method with no carry , 1 carry n then 2 carry on X+X=W.
We will find only carry 2 satisfies. i.e. 2+x+x=w. i.e 2+5+5=12. so x=5 and w=2 and then 1 carry is generated so consequently w+1=A. i.e 1+2=3. So A=3
MXS*A=WXZW. ie M5S*3=25Z2.
now , 3*s=2 so s must be 4. and
then wx=25 so 3 * 8 + carry 1=25.
NOW, MXS*N=854*N.
NOw see all d digits have been used except 7,9 so 1st replace N with 7 then proceed .
854
*377
____
5978
5978
2562
_____
321958
- 9 years agoHelpfull: Yes(18) No(5)
- fist start with the clue : w+1=A
now;
A * S=W
3 * 4=2
7 * 8=6
9 * 2=8
now ;
M X S
A
-----------
W X Z W
so try with A=3 and s=4 so w =2;
so if w=2 then x can be 5 (if carry is 2)or 6(if carry is 0);
(X+X+carry=W);
now proceed with X=5;
I hope this much is sufficient for whom who wants hint only ;
- 9 years agoHelpfull: Yes(10) No(4)
- 854
*377
--------------
5978
5978-
2562--
--------------
321958 - 9 years agoHelpfull: Yes(5) No(2)
- 854*377
5978
5978-
2562-- - 9 years agoHelpfull: Yes(1) No(2)
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