Elitmus
Exam
Numerical Ability
Time and Work
P, Q and R can do a work in 20, 30 and 60 days respectively. How many days does it need to complete the work if P does the work and he is assisted by Q and R on every third day?
Options
1) 10 days
2) 14 days
3) 15 days
4) 9 days
Read Solution (Total 10)
-
- p's one day work=1/20 so p's 2 day work=1/10
P+q+r together in one day=1/10
so
in 3 days total work done is=(1/10+1/10)=1/5
so total days needed= 3*5=15 days
- 9 years agoHelpfull: Yes(19) No(2)
- P=>20 days Q=>30 days R=>60days
2days work of p=2/20=1/10
3rd day work=1/20+1/30+1/60=1/10
1/5 work cmplted in 3 days
then cmplt wrk in
15 days - 9 years agoHelpfull: Yes(7) No(0)
- Let the total unit of work to be done = 60 units
So P does 3 units in a day
Q does 2 units in a day
R does 1 unit in a day
So two days of P's work = 6 units and One day of P Q R together work = 6 units
So in three days they do total 12 units of work
So 60 units of work will be done in 3*5= 15 days Ans 3) - 9 years agoHelpfull: Yes(6) No(1)
- 15 days
p+q+r in one day 1/10
p in one day 1/2o
in 2 days 1/10
s0 1/10+1/10+1/10...........=15 days - 9 years agoHelpfull: Yes(3) No(0)
- 15 days
P can do work in 2 days= (1/10)
P,Q,R together can do work in 1 days =(1/10)
hence 15 days require to complete work - 9 years agoHelpfull: Yes(2) No(3)
- work done by p in 1 day=5%
work done by q in 1 day= 3.33%
work done by r in 1 day = 1.67%
now after three days the completed work is = 15% +(3.67+1.67)% = 20%
for completion of work it takes = 3*5 = 15 days - 9 years agoHelpfull: Yes(2) No(0)
- Ans . A 815 ,lek in laga nhi elitmus ka Hoga ye question
- 9 years agoHelpfull: Yes(1) No(1)
- let me do in chocolate method
p-20 days
q-30 days
r-60 days
LCM of these 3 is 60 chocolates
p-3 choc/day
q-2choc/day
r-1choc/day
total work for 3 days =3+3+(3+2+1)=12 choc/3days
therefore , 12 chocolates completed-3 days
60 chocolates=(60*3)/12=15 days.
so option 3 is right
so, P-60/20=3choc/day - 8 years agoHelpfull: Yes(1) No(0)
- 1. 10 days
- 9 years agoHelpfull: Yes(0) No(8)
- total unit=60
1st day=3 unit,
2nd day=3 unit
3 day=6 unit
total=3+3+6=12unit on 3 days
s0 12*5unit=3*5 days
answer will be 15 days - 9 years agoHelpfull: Yes(0) No(0)
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