out of 11 members of a family 4 are males and rest are females.the family hired three taxis on rent to see a museum.the members have to sit in car in such a way that not more the 4 members are in one car and each car has at least one male member,In how many ways the members can travel

• 4 males
  7 females
  
  possible ways of travel for the one taxi= (4C1*7C3 + 4C2*7C2 + 4C3*7C1 + 4C4)
  = 295
  then,
  
  possible ways of travel for the 3 taxis = 3*295 = 885
• 9 years agoHelpfull: Yes(5) No(1)
• t1:mff,mff,mffm,mff
  t2:mff,mfm,mff,mffm
  t3:mffm,mfff,mff,mff
• 9 years agoHelpfull: Yes(0) No(0)
• the solution given by Ms.shruthi was correct but...we have 3 more possible ways for one taxi
  as it stated in problem that not more than 4 members in one car.so we can have 3 members in one taxi.
  
  4C1 * 7C2 + 4C2 * 7C1 + 4C3 = 130
  so 295 + 130 = 425
  425 * 3 = 1275
• 9 years agoHelpfull: Yes(0) No(2)