x + 3x^2 + 5x^3 + 7x^4+ . . . . . +99x^49 is divided by (x-1) .then what will be the remainder?

• i am using synthesis division
  for example we will take x + 3x^2 + 5x^3 + 7x^4 is devided by x-1
  the factors of above equation 7 5 3 1
  
  step 1:
  Bring down the leading coefficient (1), multiply it with a (1), and
  3. write that product (7·1 ) in the second column:
  1 7 5 3 1
  7
  ------------------
  7 12
  stpe 2:
  
  Bring down the leading coefficient (1), multiply it with a (2), and
  3. write that product (12· 1) in the second column:
  1 7 5 3 1
  7 12
  ------------------
  7 12 15
  
  STEP 3:
  
  Bring down the leading coefficient (1), multiply it with a (2), and
  3. write that product (15· 1) in the second column:
  1 7 5 3 1
  7 12 15
  ------------------
  7 12 15 16
  SO THE REMINDER IS 16
  
  FOLLOW THIS PROCEDURE TO THIS PROBLEM
  THE ABOVE EQUATION FACTORS ARE ODD NUMBERS UPTO 99
  THE SUM OF ODD NUMBERS FORMULA IS N^2
  WE HAVE 50 ODD NUMEBRS FROM 1 TO 99
  50^2 =2500
  THE REMINDER OF ABOVE PROBLEMI IS : 2500
• 9 years agoHelpfull: Yes(0) No(0)