a person travels from his house to office from 11 10am to 11 50 am and covers a distence of

time = 11:10 am to 11:50 am = 40 min = 40/60 =2/3 hr

distance = 13.4 km

avg speed = 13.4 /2/3 = 20.3 km/hr
9 years agoHelpfull: Yes(13) No(11)
11:10 am to 11:50 am = 40 min=4060=23hrs
dist = 13.4km
avg speed=13.4*32=20.1kmph
9 years agoHelpfull: Yes(10) No(5)
what would be the second round for GTS .
9 years agoHelpfull: Yes(6) No(1)
simply 13.4/40/60=20.1kmph
9 years agoHelpfull: Yes(5) No(0)
time=11:50-11:10=40min=2/3hour
distance=13.4km
speed=13.4*3/2=20.1km/h
8 years agoHelpfull: Yes(3) No(0)
13.4/(2/3)=20.1
9 years agoHelpfull: Yes(1) No(0)
time=11:50-11:10=40 min
d=134
s=13.4*3/2=20kmph
8 years agoHelpfull: Yes(1) No(1)
time = 11:10 am to 11:50 am = 40 min = 40/60 =2/3 hr

distance = 13.4 km

avg speed = 13.4 /2/3 = 20.1 km/hr
7 years agoHelpfull: Yes(0) No(0)

a person travels from his house to office from 11:10am to 11:50 am and covers a distence of 13.4km. find the average speed of the person.