Elitmus
Exam
Category
if (n^2-33),(n^2-31), (n^2-29) are prime numbers
then number of possible values of n , if n is integer?
op: 1,2,6,none
Read Solution (Total 4)
-
- i think,
n=6 is only possible value. - 9 years agoHelpfull: Yes(8) No(0)
- 6^2-33=3 prime repeats similarily for 8,10,12,14,16... so ans is 6 :)
6^2-31=5
6^2-29=7 - 9 years agoHelpfull: Yes(0) No(8)
- @RAVI BHUSHAN
n= 8,10,12,14,16 is not satisfying
8^2-31 = 33 is not prime ..... - 9 years agoHelpfull: Yes(0) No(0)
- The answer is 1, as only 1 value of N is acceptable i.e. 6 . So read the question carefully before answering.
- 8 years agoHelpfull: Yes(0) No(0)
Elitmus Other Question
how many pairs of positive integers m,n satisfy
1/m + 4/n = 1/12
op: 3,4,5,6,7
how many pairs of positive integers m,n satisfy
1/m + 4/n = 1/12, given n is odd integer less than 60
op: 3,4,5,6,7