if (n^2-33),(n^2-31), (n^2-29) are prime numbers
then number of possible values of n , if n is integer?

op: 1,2,6,none

• i think,
  n=6 is only possible value.
• 9 years agoHelpfull: Yes(8) No(0)
• 6^2-33=3 prime repeats similarily for 8,10,12,14,16... so ans is 6 :)
  6^2-31=5
  6^2-29=7
• 9 years agoHelpfull: Yes(0) No(8)
• @RAVI BHUSHAN
  n= 8,10,12,14,16 is not satisfying
  8^2-31 = 33 is not prime .....
• 9 years agoHelpfull: Yes(0) No(0)
• The answer is 1, as only 1 value of N is acceptable i.e. 6 . So read the question carefully before answering.
• 9 years agoHelpfull: Yes(0) No(0)